Challenge 2 — Solution

Task: Define a class Dog that extends Animal from Challenge 1,
overriding speak() to log "{name} barks." instead, while still
calling the parent's speak() first using super.speak(). Create a
Dog instance and call speak() on it.

class Animal {
    constructor(name) {
        this.name = name;
    }

    speak() {
        console.log(`${this.name} makes a sound.`);
    }
}

class Dog extends Animal {
    speak() {
        super.speak();
        console.log(`${this.name} barks.`);
    }
}

const rex = new Dog("Rex");
rex.speak();


Expected output:

Rex makes a sound.
Rex barks.


Notes:
- Dog has no constructor of its own here, so Animal's constructor
  runs automatically when "new Dog("Rex")" is called — there was no
  need to write a constructor just to pass name through unchanged.
- super.speak() explicitly calls Animal's original speak() method,
  which is why "makes a sound" still prints even though Dog's own
  speak() has completely overridden the method for Dog instances.
- this.name works correctly inside Dog's speak() because Animal's
  constructor already set it, even though Dog itself never mentions
  name directly.