QUANTUM PHYSICS FUNDAMENTALS - Chapter 1, Exercise 2 Solution ========================================================== Finding Frequency from Photon Energy PROBLEM ------- A photon has an energy of 4.14 x 10^-19 J. Using E = hf, calculate its frequency. SOLUTION -------- Starting from Planck's relation: E = h f Rearranged to solve for frequency: f = E / h Substitute the given values: E = 4.14 x 10^-19 J h = 6.626 x 10^-34 J.s f = (4.14 x 10^-19) / (6.626 x 10^-34) f = 6.25 x 10^14 Hz (approximately) ANSWER: The photon's frequency is approximately 6.25 x 10^14 Hz. ---- WHY THIS WORKS AS AN ANSWER Since E = hf is a simple direct proportionality with h as a fixed constant, dividing the given energy by h directly recovers the frequency - the same rearrangement technique used throughout this course whenever two of the three quantities in a proportional relationship are known. This particular frequency, 6.25 x 10^14 Hz, falls within the real visible light spectrum (toward the blue/violet end), consistent with the chapter's own examples of green and red light sitting at somewhat lower frequencies.