CLASSICAL MECHANICS & THERMODYNAMICS - Chapter 5, Exercise 2 Solution ========================================================== Torque on a Bicycle Pedal PROBLEM ------- A cyclist applies a force of 250 N to a bicycle pedal, perpendicular to the 0.17 m pedal crank arm. Calculate the torque produced. SOLUTION -------- Using the torque formula: tau = r F sin(theta) Substitute the given values: r = 0.17 m F = 250 N theta = 90 degrees (force is perpendicular to the crank arm) tau = 0.17 x 250 x sin(90 degrees) tau = 0.17 x 250 x 1 tau = 42.5 N.m ANSWER: The torque produced is 42.5 N.m. ---- WHY THIS WORKS AS AN ANSWER Because the force is applied perpendicular to the crank arm (theta = 90 degrees), sin(90 degrees) = 1, so the full force contributes entirely to rotation with none of it "wasted" - the same reasoning used for the chapter's own wrench example. This is also exactly why cyclists are taught to push perpendicular to the pedal crank through the power stroke of a pedal rotation: any component of force that isn't perpendicular to the crank arm (for example, pushing straight down when the pedal is at the very top or bottom of its circle) produces less torque, or even none at all, for the same physical effort.