Capstone: A Real Worked Mechanical/Thermal System

Classical Mechanics & Thermodynamics
Course 1 · Chapter 10 · Capstone: A Real Worked Mechanical/Thermal System

Nine chapters have built two toolkits: one for motion, force, and gravity (Chapters 1–6), and one for heat, engines, and entropy (Chapters 7–9). This capstone runs a single, continuous, fully worked system through every one of them — a small steam-launched roller coaster car, from the boiler that powers its launch to the braking collision that finally stops it.

The System

A steam piston launches a 400 kg roller coaster car (with rider) along a straight 3 m launch track. The car then climbs into a 2.5 m-radius vertical loop, completes the circuit, and returns to ground level, where it couples with a stationary 600 kg braking car to bring the ride safely to rest. Every number below is carried forward, unmodified, from the step before it.

Step 1 · Chapter 9 (Kinetic Theory of Gases)

Before launch, superheated steam fills the 0.05 m³ piston chamber at T = 400 K, with n = 3 mol present. Using the ideal gas law to find the steam's pressure:

P = nRT/V
P = (3 × 8.314 × 400) / 0.05
P ≈ 199,540 Pa ≈ 200,000 Pa
Step 2 · Chapter 7 (The First Law of Thermodynamics)

As the steam expands and drives the piston outward, the boiler supplies Q = 45,000 J of heat during the power stroke. The piston has area A = 0.05 m² and travels d = 3 m, so the swept volume is ΔV = Ad = 0.15 m³. Treating the expansion as roughly constant-pressure, the work done by the steam is:

W = PΔV = 200,000 × 0.15 = 30,000 J
ΔU = Q − W = 45,000 − 30,000 = 15,000 J

15,000 J of heat remains in the steam as increased internal energy; the other 30,000 J becomes the mechanical work that launches the car.

Step 3 · Chapter 8 (Heat Engines)

Measured over a complete piston cycle (this power stroke plus the return stroke needed to reset it), the boiler-and-piston system converts heat into net usable work at a real, measured 20% overall efficiency. With steam entering at TH = 400 K and exhaust condensing at roughly TC = 300 K, the Carnot maximum for any engine operating between these two temperatures is:

ηCarnot = 1 − 300/400 = 0.25, or 25%

The engine's real 20% efficiency sits honestly below this theoretical 25% ceiling — exactly as Chapter 8's own theory requires, since no real, imperfectly reversible engine can reach, let alone exceed, the Carnot limit.

Step 4 · Chapter 2 (Newton's Second Law)

The steam's pressure acts on the piston's full area to produce the launch force:

F = PA = 200,000 × 0.05 = 10,000 N
a = F/m = 10,000 / 400 = 25 m/s²
Step 5 · Chapter 1 (Kinematics)

Using v² = u² + 2as over the 3 m stroke (u = 0):

v² = 2 × 25 × 3 = 150
v = √150 ≈ 12.25 m/s

The launch takes t = v/a = 12.25/25 ≈ 0.49 s.

Step 6 · Chapter 3 (Work, Energy & Power)

Checking the mechanical work directly:

W = Fd = 10,000 × 3 = 30,000 J
KE = ½mv² = ½ × 400 × 150 = 30,000 J
🔗 A Guaranteed, Not Coincidental, Match This 30,000 J exactly matches Step 2's own thermodynamic work calculation, PΔV. That agreement isn't a coincidence: since F = PA and ΔV = Ad, the two formulas W = Fd and W = PΔV are algebraically the same equation, just written in mechanical and thermodynamic language respectively — a genuine, structural link between this course's own two halves.

Power output during the launch: P = W/t = 30,000/0.49 ≈ 61,200 W, or about 61.2 kW.

Step 7 · Chapter 6 (Gravity & Conservation of Energy)

The car enters the loop (radius r = 2.5 m) at ground level with its full 30,000 J of kinetic energy. At the top of the loop (height = 2r = 5 m), some of that energy has converted to gravitational potential energy:

PEtop = mg(2r) = 400 × 9.81 × 5 = 19,620 J
KEtop = 30,000 − 19,620 = 10,380 J
vtop = √(2 × 10,380 / 400) ≈ 7.20 m/s
Step 8 · Chapter 5 (Circular Motion) — A Real Safety Check

At the top of a loop, the car needs a minimum speed for gravity alone to supply the required centripetal force (mg = mv²min/r):

vmin = √(gr) = √(9.81 × 2.5) ≈ 4.95 m/s

The car's actual speed at the top, 7.20 m/s, comfortably exceeds this 4.95 m/s minimum — confirming the loop is safely designed, with real margin to spare, before a single rider ever boards.

Step 9 · Chapter 4 (Momentum & Collisions) — Full Circle

Having completed the frictionless loop, the car returns to ground level with its full original speed, v ≈ 12.25 m/s, and couples with a stationary 600 kg braking car — a perfectly inelastic collision:

mcarvcar = (mcar + mbrake)vfinal
400 × 12.25 = 1000 × vfinal
vfinal ≈ 4.90 m/s

Checking the kinetic energy: before coupling, KE ≈ 30,000 J; after, KE = ½(1000)(4.90²) ≈ 12,000 J. Roughly 18,000 J has vanished from the mechanical system entirely.

🔗 The Course's Own Full Circle That "lost" 18,000 J was never destroyed — per Chapter 3's own conservation of energy and Chapter 7's own First Law, it converted into heat in the coupling mechanism's own metal, exactly the same kind of conversion Chapter 3's Joule paddle-wheel experiment demonstrated in reverse. This course opened its thermodynamics half by turning heat into motion (Steps 1–6, the steam launch); it closes by turning motion back into heat (this braking collision) — the same underlying physics, run in opposite directions, tying mechanics and thermodynamics together as genuinely one subject rather than two.

Every Chapter, In One System

StepChapterWhat It Contributed
19 — Kinetic Theory of GasesIdeal gas law gives the steam's real pressure, ~200,000 Pa
27 — The Laws of ThermodynamicsFirst Law: ΔU = Q − W for the power stroke
38 — Heat Engines & EntropyReal efficiency (20%) checked against the Carnot ceiling (25%)
42 — Newton's Three LawsF = PA gives launch force; F = ma gives acceleration
51 — KinematicsSUVAT gives launch speed and launch time
63 — Work, Energy & PowerW = Fd confirms KE; power output during launch
76 — Gravity RevisitedConservation of energy gives speed at the top of the loop
85 — Circular Motion & Rotational DynamicsMinimum loop speed confirms a safe design
94 — Momentum & CollisionsPerfectly inelastic braking collision; energy lost to heat

Hands-On Exercises

Exercise 1
A redesigned piston has area A = 0.06 m^2 and the same steam pressure, P = 200,000 Pa, over the same 3 m stroke, launching a lighter 350 kg car. Find the new launch force, acceleration, and launch speed.
→ Solution
Exercise 2
Suppose the loop's radius were increased to 4 m instead of 2.5 m, with the car still entering the loop with 30,000 J of kinetic energy at ground level (mass unchanged, 400 kg). Using conservation of energy and the minimum-speed condition, determine whether the car can safely complete this larger loop.
→ Solution
Exercise 3
Explain, using both the First Law of Thermodynamics (Chapter 7) and conservation of energy (Chapter 3), exactly where the roughly 18,000 J of kinetic energy "lost" in the final braking collision (Step 9) actually goes - and why calling it "lost" is only accurate from the mechanical system's own point of view, not from the perspective of the universe's total energy.
→ Solution

Course Complete

Classical Mechanics & Thermodynamics is now complete, 10/10 chapters — from Chapter 1's own real, corrected Galileo tower story through this capstone's full mechanical-and-thermal system. Along the way, this course found a genuine recurring pattern: the popular, tidy version of a scientific story (Galileo's tower, "Newton's cradle," Newton's apple, the Zeroth Law's own name) is consistently less accurate, and less interesting, than the messier real history behind it.

Electromagnetism & Relativity (electromag1) is the second half of the original "Classical Physics" split, and remains ready to generate as the direct next course in this Science subject — picking up the same real, verify-everything discipline for electricity, magnetism, and the real crisis that led to relativity.