Basic Electronics, Chapter 3: Challenge 1 solution (decode, encode and power) (a) Decoding. Digit bands first, then the multiplier, then tolerance. brown-black-orange-gold 1, 0, x 1 k, gold = 5 % -> 10 k ohm +/-5 % range: 10,000 x 0.95 = 9,500 ohm to 10,000 x 1.05 = 10,500 ohm yellow-violet-red-gold 4, 7, x 100, gold = 5 % -> 4.7 k ohm +/-5 % range: 4,700 x 0.95 = 4,465 ohm to 4,700 x 1.05 = 4,935 ohm green-blue-brown-brown (4-band: brown tolerance = 1 %) 5, 6, x 10, brown = 1 % -> 560 ohm +/-1 % range: 560 x 0.99 = 554.4 ohm to 560 x 1.01 = 565.6 ohm red-red-black-red-brown (5-band: three digits, multiplier, tolerance) 2, 2, 0, x 100, brown = 1 % -> 220 x 100 = 22,000 ohm = 22 k ohm +/-1 % range: 22,000 x 0.99 = 21,780 ohm to 22,000 x 1.01 = 22,220 ohm (b) Encoding. 330 ohm, 5 % = 33 x 10 -> orange, orange, brown, gold 6.8 k, 5 % = 68 x 100 -> blue, grey, red, gold 100 k, 1 % (5-band) = 100 x 1 k -> brown, black, black, orange, brown (digits 1,0,0 then multiplier orange = x 1 k, then brown = 1 %) (c) Derating a 1/4 W resistor at 100 C. P_allowed = P_rated x (155 - T) / (155 - 70) = 0.25 x (155 - 100) / 85 = 0.25 x 55 / 85 = 0.1618 W The actual 0.15 W is below 0.162 W, so it is within the limit, but it is 0.15 / 0.1618 = 93 % of the derated limit: far too little margin. A 1/2 W part would allow 0.5 x 55 / 85 = 0.3235 W, so 0.15 W would be 46 %. Better choice: the 1/2 W resistor. (d) 12 V across 470 ohm. P = V^2 / R = 144 / 470 = 0.3064 W Current check: I = 12 / 470 = 25.5 mA; P = I^2 R = 0.0255^2 x 470 = 0.306 W. Same. Rule: P must be at most 50 % of the rating, so rating >= 0.3064 / 0.5 = 0.613 W. 1/4 W (0.25 W): P is 123 % of the rating -> fails 1/2 W (0.5 W): P is 61 % of the rating -> fails the 50 % rule 1 W: P is 31 % of the rating -> passes Answer: use a 1 W resistor (or reduce the voltage or increase the resistance). Checklist [ ] read from the end nearest a band edge, digits then multiplier then tolerance [ ] 4-band: 2 digits; 5-band: 3 digits [ ] tolerance range = value x (1 +/- tolerance) [ ] P = V^2/R; choose a rating of at least twice the power [ ] derate for temperature above 70 C