Exercise 1: Computing the Effective Address of LD A,(IX+5) — Possible Solution
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GIVEN
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IX = $4000
Instruction: LD A,(IX+5)

APPLYING THE FORMULA
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Per this chapter's own explanation, indexed addressing with
displacement computes its effective address as:

  effective address = (value in the index register) + displacement

Substituting the given values:

  effective address = $4000 + 5
                     = $4005

RESULT
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LD A,(IX+5) reads the byte stored at address $4005.

WHY THIS WORKS AS AN ANSWER
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It applies the chapter's own stated formula directly to the given
register value and displacement, showing the arithmetic explicitly
rather than just stating the final address.