Exercise 10: A Small Formatted Table — Possible Solution
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students = [("Priya", 88.5), ("Tom", 72.0), ("Aisha", 95.25)]

total = 0
for name, score in students:
    print(f"{name:<10}{score:>8.1f}")
    total += score

average = total / len(students)
print(f"{'Average':<10}{average:>8.1f}")

Output:
Priya         88.5
Tom           72.0
Aisha         95.2
Average       85.2

WHY THIS WORKS AS AN ANSWER
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{name:<10} left-aligns each student's name inside a 10-character
field, and {score:>8.1f} right-aligns each score inside an 8-character
field with exactly one decimal place — the same two-specifier pattern
as this lesson's receipt case study, just applied to a different pair
of columns. Aisha's 95.25 and the average of 85.25 both land exactly
on a rounding tie (halfway between two displayed values), and Python's
:.1f rounds ties to the nearest EVEN final digit rather than always
rounding up — so 95.25 becomes 95.2 (2 is even) and 85.25 becomes 85.2
(also even), not 95.3/85.3 as "round half up" would suggest. This is
the same "banker's rounding" behaviour Python's own round() function
uses, and it only becomes visible when a value is exactly on a .x5
boundary, unlike Exercise 5's 23.745, which wasn't a clean tie. The
running total is accumulated in the loop exactly like a normal sum,
then divided by len(students) once the loop ends to get the average —
the average line reuses the same field widths so it lines up under
the columns above it.