Challenge 2: A Pipeline With No Terminal Operation — Possible Solution
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LazyDemo.java:

import java.util.List;

public class LazyDemo {
    public static void main(String[] args) {
        List<String> names = List.of("Alice", "Bob", "Carol");

        names.stream()
            .filter(n -> {
                System.out.println("Checking: " + n);
                return n.length() > 3;
            });

        // No output at all appears above this comment when run.
        // filter() is an intermediate operation -- it only ever
        // DESCRIBES a step in the pipeline, it never actually
        // executes it. Nothing forces the stream to run its
        // elements through that filter, because no terminal
        // operation (collect, forEach, reduce, etc.) was ever
        // called. The lambda inside filter() -- including its
        // println side effect -- is simply never invoked.
        System.out.println("Program finished.");
    }
}

Output:

    Program finished.

WHY THIS WORKS AS AN ANSWER
------------------------------
This reproduces the chapter's own lazy-evaluation example exactly --
a filter with a print side effect and no terminal operation -- and
the comment correctly identifies that the absence of any terminal
operation is the reason the filter's lambda body, print included,
never runs at all.