Challenge 1: Filtering a List<int> with LINQ Method Syntax — Possible Solution
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Program.cs:

List<int> numbers = new() { 3, 15, 8, 22, 1, 40, 7 };

var bigNumbers = numbers.Where(n => n > 10);

foreach (var n in bigNumbers)
{
    Console.WriteLine(n);
}

Output:

    15
    22
    40

Explanation:
Where(n => n > 10) is LINQ's method-syntax form, taking a lambda
predicate and returning only the elements that satisfy it -- in
order, and without modifying the original numbers list at all. The
result (bigNumbers) is itself an IEnumerable<int>, which foreach can
iterate directly, exactly the same List<T>/foreach combination the
chapter introduced earlier in the same lesson.

WHY THIS WORKS AS AN ANSWER
------------------------------
This uses LINQ's method syntax (.Where()) exactly as the chapter's
own numbers example demonstrates, applied to a List<T> rather than a
plain array, confirming LINQ works identically across different
IEnumerable<T> sources.