Challenge 1: Printing a 6-Element Array Using the sizeof Trick — Possible Solution
====================================================================

#include <stdio.h>

int main() {
    int nums[6] = {10, 20, 30, 40, 50, 60};
    int count = sizeof(nums) / sizeof(nums[0]);

    for (int i = 0; i < count; i++) {
        printf("%d\n", nums[i]);
    }
    return 0;
}

Output:

    10
    20
    30
    40
    50
    60

WHY THIS WORKS AS AN ANSWER
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count is computed correctly because it's calculated in main, the exact
scope where nums was declared -- sizeof(nums) gives the array's total
byte size, sizeof(nums[0]) gives one element's byte size, and dividing
the two gives the element count (6), used directly as the loop's upper
bound rather than hardcoding the number 6 separately.