Challenge 1: Integer vs. Double Division — Possible Solution
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#include <stdio.h>

int main() {
    int int_result = 7 / 2;
    double double_result = 7.0 / 2;
    printf("%d\n", int_result);
    printf("%f\n", double_result);
    return 0;
}

Output:

    3
    3.500000

Explanation: 7 / 2 divides two ints, so the result is computed using
integer division, which truncates toward zero -- 3.5 becomes 3, with
the fractional part simply discarded (not rounded). 7.0 / 2 has a
double as one operand, which forces the whole expression to be
evaluated using floating-point division instead, producing the exact
3.5 result.

WHY THIS WORKS AS AN ANSWER
------------------------------
This demonstrates the chapter's own point directly: the SAME numeric
relationship (7 divided by 2) produces genuinely different results
depending purely on operand types, and explains truncation (discarding
the fraction) as distinct from rounding, which is the specific
misunderstanding this gotcha usually causes.