Exercise 2: K-Map for xy + x'y — Possible Solution
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GIVEN
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f(x,y) = xy + x'y (same function as Exercise 1)

STEP 1: BUILD THE TRUTH TABLE
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x=0,y=0: f=0
x=0,y=1: f=1
x=1,y=0: f=0
x=1,y=1: f=1

STEP 2: DRAW THE 2x2 K-MAP
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      y=0   y=1
x=0    0     1
x=1    0     1

STEP 3: IDENTIFY THE GROUP OF ADJACENT 1s
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The two 1-cells are at (x=0,y=1) and (x=1,y=1) - these sit in the
same column (y=1) and are vertically adjacent, differing only in
x. This is a group spanning the ENTIRE y=1 column - the widest
possible group for a 2-variable map, meaning the variable that
changes across the group (x) is eliminated entirely, leaving only
the variable that stays fixed (y=1).

RESULT
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The K-map group gives: y

This matches Exercise 1's own algebraically-derived result exactly
(f(x,y) = y) - the same simplification, reached by spotting an
adjacent pair on the grid instead of manipulating the algebraic
expression.

WHY THIS WORKS AS AN ANSWER
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The K-map is built directly from the actual truth table (not
guessed), the specific adjacency (differing only in x) is
identified explicitly as the reason x drops out, and the result is
cross-checked against Exercise 1's own independently-derived
algebraic answer rather than presented as a fresh, unconnected
result.