CHALLENGE 1: Navigating a Scene Tree
====================================================================

TASK
----
Build a scene with a Node2D root and three Node2D children named
"Head," "Body," and "Feet." Write a script on the root that uses
get_children() to print the name of every child, and separately
uses $Body to print that one child's name directly.

SCENE STRUCTURE
----------------
Root (Node2D)
|-- Head (Node2D)
|-- Body (Node2D)
|-- Feet (Node2D)

SOLUTION CODE (attached to Root)
----------------------------------
extends Node2D

func _ready() -> void:
    for child in get_children():
        print(child.name)

    print("Directly via $Body: ", $Body.name)

OUTPUT
------
Head
Body
Feet
Directly via $Body: Body

WHY THIS WORKS AS AN ANSWER
----------------------------
get_children() returns an Array containing every direct child of the
node it's called on - here, Root's own three children - in the order
they appear in the Scene panel. Looping over that Array with a
for-in loop (from Chapter 2) and printing each child's .name property
lists all three without needing to know their names in advance.

$Body is the shorthand form of get_node("Body") - it reaches that
one specific child directly by its exact name, which only works
because "Body" is a real, correctly-spelled child of Root. This is
the more common way to reach a *specific*, already-known node in
real code, while get_children() is more useful when you need to
process every child generically without caring what each one is
called.